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A metal rod of length 1m rotates about its one end in a plane at right angles to a horizontal magnetic field of induction 7/22xx10^-4T. If its frequency of rotation is 10 Hz, then what is the magnitude of induced e.m.f.? |
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Answer» Solution :FLUX `PHI` = B.A Area swept/sec = dA/dt = F.`pir^2` ` therefore E = 7/22xx10^-4xx10xx22/7xx1^2` = imV |
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