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A metal rod of resistance 20 Omega is fixed along a diameter of a conducting ring of radius 0.1m and lies on x-y plane. There is a magnetic field B =(50T)hatk. The ring rotates with an angular velocity omega=20 rad //s about its axis. An external resistance of 10 Omega is connected across the centre of the ring and rim. The current through external resistance is |
Answer» Solution : The equivalent circuit is  `E=(1)/(2)Bl^(2) omega =(1)/(2) XX 50 xx 0.1 xx 0.1 xx 20`, `:.` e = 5 V Hence the current through the EXTERNAL resistance is `i=(e)/(R)"":. i=(5)/(15)=(1)/(3)` AMP |
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