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A metal rod of resistance 20Omegais fixed along a diameter of a conducting ring of radius 0.1m and lies on x-y plane. There is a magnetic field vecB = (50T)hatk. The ring rotates with an angular velocity omega= 20rad /s about its axis. An external resistance of 10Omegais connected across the centre of the ring and rim. The current through external resistance is |
Answer» Solution : `e = 1/2 Bl^2 omega = 1/2 xx 50 xx 0.1 xx 0.1 xx 20` ` therefore e = 5V` HENCE the current through the external RESISTANCE is `i = e/R therefore i = 5/15 = 1/3 `AMP 
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