A metal X reacts with aqueous NaOH solution to form Y and a highly inflammalbe gas. Solution Y is heated and `CO_(2)` is poured through it. Z precipitates out and `Na_(2)CO_(3)` is formed. Z on the heating gives `AI_(2)O_(3)`. Identify X,Y and Z. X Y ZA. `Al, NaAIO_(2), AI(OH)_(3)`B. `AI_(2)O_(3), NaAIO_(2), AI_(2)CO_(3)`C. `AI_(2)O_(3), [Na_(2)AIO_(2)]^(+) OH^(-), AI(OH)_(3)`D. `AI, AI(OH)_(3) AI_(2)O_(3)`

A metal X reacts with aqueous NaOH solution to form Y and a highly inf

1.	A metal X reacts with aqueous NaOH solution to form Y and a highly inflammalbe gas. Solution Y is heated and `CO_(2)` is poured through it. Z precipitates out and `Na_(2)CO_(3)` is formed. Z on the heating gives `AI_(2)O_(3)`. Identify X,Y and Z. X Y ZA. `Al, NaAIO_(2), AI(OH)_(3)`B. `AI_(2)O_(3), NaAIO_(2), AI_(2)CO_(3)`C. `AI_(2)O_(3), [Na_(2)AIO_(2)]^(+) OH^(-), AI(OH)_(3)`D. `AI, AI(OH)_(3) AI_(2)O_(3)`
Answer» Correct Answer - A `underset((X))(2AI) + 2NaOH + 2H_(2) O to underset((Y))(2NaSIO_(2)) + 3H_(2)` `underset((Y))(2NaAIO_(2)) + CO_(2) + 3H_(2)O to underset((Z))(2AI(OH)_(3)) + Na_(2) CO_(3)` `underset((Z))(2AI(OH)_(3)) to AI_(2)O_(3) + 3H_(2) O`

Discussion

No Comment Found

Related InterviewSolutions

An amorphous solid (X) burns in air to form a gas ( Y) which turns lime water milky. This gas decolourises aqueous solution of acidified `KMnO_(4).` Gas (Y) reacts with oxygen to give another gas (Z) which is responsible for acid rain. X, Y and Z areA. `{:("X","Y","Z"),(C, CO,CO_(2)):}`B. `{:("X","Y","Z"),(S, SO_(2),SO_(3)):}`C. `{:("X","Y","Z"),(P, P_(2)O_(3),P_(2)O_(5)):}`D. `{:("X","Y","Z"),(S, SO_(3),H_(2)SO_(4)):}`
vii. The stability of dihalides of ` Si, Ge , Sn` and Pb increases steadily in the sequence :A. `PbX_(2) lt lt SnX_(2) lt lt GeX_(2) lt lt SiX_(2)`B. `GeX_(2) lt lt SiX_(2) lt lt SnX_(2) lt lt PbX_(2)`C. `SiX_(2) lt lt GeX_(2) lt lt PbX_(2) lt lt SnX_(2)`D. `SiX_(2) lt lt GeX_(2) lt lt SnX_(2) lt lt PbX_(2)`
`NO_(2)`,a red -brown poisonous gas is prepared in the laboratory by heatingA. `NaNO_(3)`B. `NH_(4)NO_(3)`C. `Pb(NO_(3))_(2)`D. `KNO_(3)`
Why has it been difficult to study the chemistry of radon?A. it is radioactive with short half lifeB. it is chemically inertC. its compound is not isolatedD. it has low boiling point
`SF_(6)` is not easily hydrolysed whereas `SF_(4)` can be. Assign reason.
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power. A. `ClO_(4)^(-)gt IO_(4)^(-) gt BrO_(4)^(-)`B. `IO_(4)^(-) gt BrO_(4)^(-) gt ClO_(4)^(-)`C. `BrO_(4)^(-) gt IO_(4)^(-) gt ClO_(4)^(-)`D. `BrO_(4)^(-) gt ClO_(4)^(-) gt IO_(4)^(-)`
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power. Ion `" " CiO_(4)^(-) " " IO_(4)^(-) " " BrO_(4)^(-)` Reduction `" " E^(Theta)=1.19 V " " E^(Theta)=1.65 V " " E^(Theta)=1.74` potential `E^(Theta)//V`A. `ClO_(4)^(-) gt IO_(4)^(-) gt BrO_(4)^(-)`B. `IO_(4)^(-) gt BrO_(4)^(-) gt ClO_(4)^(-)`C. `BrO_(4)^(-) gt IO_(4)^(-) gt ClO_(4)^(-)`D. `BrO_(4)^(-) gt ClO_(4)^(-)IO_(4)^(-)`
`SO_(2)+NaClO_(3) overset(H^(+))to`
Aluminium exhibits +3 oxidation state. As we move down the group, +1 oxidation state gets more stable. This is a consequence ofA. increaseing size of the atomB. inert pair effectC. electron deficient natureD. `p pi - p pi` bonding
Which of the following Lewis acids exhibits maximum acidic strength?A. `BI_(3)`B. `BBr_(3)`C. `BCl_(3)`D. `BF_(3)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment