A metallic rod of mass per unit length 0.5kgm^(-1) is lying horizontally on a smooth inclined plane which makes an angle of 30^(@) with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction 0.25 T is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is.

A metallic rod of mass per unit length 0.5kgm^(-1) is lying horizontal

1.	A metallic rod of mass per unit length 0.5kgm^(-1) is lying horizontally on a smooth inclined plane which makes an angle of 30^(@) with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction 0.25 T is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is.
Answer» 11.32 A 7.14 A 14.76 A 5.98 A Solution :The METALLIC rod of mass is shown by `ilBcosthetaandmgsintheta`. To keep rod in stationary, `mgsintheta=ilBcostheta` `thereforemg TANTHETA=ilB` `thereforei=(mg tantheta)/(LB)` `thereforei=(m/l)(g tantheta)/B` `thereforei=(0.5xx9.8xxtan30^(@))/0.25` `thereforei=(0.5xx9.8xx1)/0.25` `thereforei=11.316A` `thereforei~~11.32A`

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