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A metallic wire of resistance 12Omegais bent to form a square. The resistance between two diagonalpoints would be |
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Answer» `12 Omega ` When a metallic WIRE of resistance 12 `Omega`is bent to form a square ABCD as shown in Fig., the resistance of each side of square is `R = 12/4 = 3Omega` Between diagonal points A and C we have parallel combination of TWO ARMS each having 2 resistances of 3 `Omega`each joined in series. Hence EQUIVALENT resistance = 3`Omega` |
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