1.

A metallic wire of resistance 12Omegais bent to form a square. The resistance between two diagonalpoints would be

Answer»

`12 Omega `
`24 Omega `
`6 Omega `
`3Omega`

Solution :
When a metallic WIRE of resistance 12 `Omega`is bent to form a square ABCD as shown in Fig., the resistance of each side of square is
`R = 12/4 = 3Omega`
Between diagonal points A and C we have parallel combination of TWO ARMS each having 2 resistances of 3 `Omega`each joined in series. Hence EQUIVALENT resistance = 3`Omega`


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