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A metre stick held vertically with one end on the floor is allowed to fall. Speed of the other end when it hits the floor is : |
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Answer» Nearly 3 m/s `mg((l)/(2))=(1)/(2)IOMEGA^(2)=(1)/(2).(1)/(3)ML^(2)omega^(2)` `=MGL=(1)/(3)mv^(2)""[therefore v=lomega]` `therefore v=sqrt(3gl)=sqrt(3xx10xx1)=5.5m//s` |
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