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A milli-voltmeter of 25 milli-volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be:A. 1B. 0.05C. 0.001D. 0.01 |
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Answer» Correct Answer - C If the resistance of the meter is G then the full scale deflection current `i_(g)=(25 mV)/(G)` ampere The Value of shunt required for converting it into ammeter of range 25 ampere is `S=(i_(g)G)/(i-i_(g))` So `~~(25 mV)/(25)=0.001 Omega` |
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