1.

A milliammeter of range 10 mA has a coil of resistance 1Omega. To use it as a voltmeter ofrange 10 V, the resistance that must be connected in series with it is

Answer»

`999Omega`
`1000OMEGA`
`9Omega`
`99Omega`

SOLUTION :`R=(V)/(I_(g))-R_(g)=(10)/(10xx10^(-3))-1=999Omega`


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