A mirror of radius of curvature 20cm and an object which is placed at a distance of 15cm are both moving with velocities `1ms^(-1)` and `10ms^(-1)` as shown in Fig. Fing the velocity of image at this situation.

A mirror of radius of curvature 20cm and an object which is placed at

1.	A mirror of radius of curvature 20cm and an object which is placed at a distance of 15cm are both moving with velocities `1ms^(-1)` and `10ms^(-1)` as shown in Fig. Fing the velocity of image at this situation.
Answer» Using `1/v+1/u=2/R,` we get `1/v-1/(15)=-1/(10)rArr v=-30cm` Now, using `V_(im) = -(v^(2))/(u^(2))V_(OM)` `(V_(i)-v_(m))=-(v^(2))/(u^(2))(V_(o)-V_(m))` `rArr V_(i)-(1)=-((-30)^(2))/((-15)^(2))[(-10)-(1)]` `rArr V_(i)=45cm s^(-1)` So, the image will move with veloxity `45 cms^(-1)`.

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