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InterviewSolution
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A mixture contain 3.2g methanol (molecular mass =32 u) and 4.6 g ethanol (molecular mass =46 u) Find the mole fraction of each component. |
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Answer» Solution :Number of moles of methanol `n_1 = 3.2/32=0.1` Number of moles of ETHANOL `n_2 = 4.6/46=0.1` MOLE FRACTION ethanol`=0.1/(0.1+0.1)= 0.1/0.2= 0.5 because x_("Methanol") = 1- 0.5= 0.5` |
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