1.

A mixture of aluminium and zinc weighning 1.67 g was completely dissolved in acid and evolved 1.69 litres of hydrogen at NTP. What was the weight of

Answer»

Solution :EQ. of METAL= `(0.43)/E ` ( eq. wt of metal `-= `E)
`:. ` m.e of metal ` = (0.43)/E xx 1000 = 430/E "" …(Eqn.3)`
m.e of total `H_(2)SO_(4)`solution` = 1 xx 50 = 50 "" …(Eqn. 1)`
Butm.e of `H_(2)SO_(4)` reacted with metal = m.e of the metal
`= (430)/E `
` :. ` m.e of unreached `H_(2)SO_(4) = ( 50 - 430/E)`
Again m.e of unreacted `H_(2)SO_(4)` = m.e of NaOH . ....(Eqn.2)
` :.E = 12.01 ` .


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