A mixture of CaCl_(2) and NaCl weighing 4.44 g is treated with sodium carbonate solution to precipitate all the Ca^(+2)ions as calcium carbonate The calcium carbonate so obtained is heated strongly to get 0.56 g of CaO . The percentage of NaCl in the mixture (atomic mass of Ca=40) is

A mixture of CaCl_(2) and NaCl weighing 4.44 g is treated with sodium

1.	A mixture of CaCl_(2) and NaCl weighing 4.44 g is treated with sodium carbonate solution to precipitate all the Ca^(+2)ions as calcium carbonate The calcium carbonate so obtained is heated strongly to get 0.56 g of CaO . The percentage of NaCl in the mixture (atomic mass of Ca=40) is
Answer» A) 75 B) `30.6` C) 25 D) `69.4` Solution :Concerned reaction is `underset("100 G")(CaCO_(3))overset(Delta)(to)underset("56 g")(CaO)+CO_(2)` 56 g of `CaO` is obtained from 100 g of `CaCO_(3)" "0.56` g `CaO` is obtained by `(100)/(56)xx0.56=1"g of "CaCO_(3)`. we know that, `underset("111 g")(CaCl_(2))+Na_(2)CO_(3)tounderset("100 g")(CaCO_(3))+2NaCl` 100 g of `CaCO_(3)` is obtained by 111 g of `CaCl_(2)` 1 g of `CaCO_(3)` is obtained by `(111)/(100)=1.11` g of `CaCl_(2)` Weight of `NaCl=4.44-1.11=3.33g` `%` age `NaCl=(3.33)/(4.44)xx100=75%`