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A mixture of formic acid and oxalic acid is heated with conc `H_2SO_4`. The gas produced is collected and treated with KOH solution, where the volume decreases by `(1)/(6)` The molar ratio of the two acids (formic acid/oxalic acid) in the original is (a). `4:1` (b). `1:4` (c). `2:1` (d). `1:2` |
Answer» Let x " mol of "HCOOH and y " mol of "`(COOH)_2` be taken `underset(x)(HCOOH)overset(H_2SO_4)toH_2O+underset(x)(CO)` `underset(y)((COOH)_2)overset(H_2SO_4)toH_2Ounderset(y)(CO)+underset(y)(CO_2)` Total " mol of "`CO+CO_2=x+2y` Total " mol of "`CO_2=y` According to the question `(x+2y)xx(1)/(6)=y` `therefore(x)/(y)=4:1` `therefore` Alternatively Mol fraction of `CO_2=(y)/(x+2y)=(1)/(6)` `therefore(x)/(y)=4:1` |
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