InterviewSolution
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InterviewSolution
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A mixture of H_(2) and O_(2) in 2:1 volume is allowed to diffuse through a porous partition what is the composition of gas coming out initially |
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Answer» Solution :We have, `(r_(H_(2)))/(r_(O_(2))) = sqrt((M_(O_(2)))/(M_(H_(2)))) = sqrt((32)/(2)) = 4`. Now since volum RATIO of `H_(2)` and `O_(2)` in the INITIAL stage is 2 :1 (given) and the ratio of there ratio is 4:1, the overall volume ratio of the GASES diffusing through the porous PARTITION at the initial stage will be 8:1. |
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