A mixture of H_(2(g)), N_(2(g)) and O_(2(g)) occuping 10 ml underwent reaction so as to from H_(2)O_(2(l)) and N_(2)H_(2(g)) as the only products causing the volume to contacts by 6ml. The remaining mixture was passed through Pyragallol causing a contraction of 1ml. to the remaining mixture excess H_(2) was added and the above reaction was repeated, causing a reduction in volume of 1ml. assuming no other products to be forming calculate the volume of H_(2) (in ml) in the initial mixture.

A mixture of H_(2(g)), N_(2(g)) and O_(2(g)) occuping 10 ml underwent

1.	A mixture of H_(2(g)), N_(2(g)) and O_(2(g)) occuping 10 ml underwent reaction so as to from H_(2)O_(2(l)) and N_(2)H_(2(g)) as the only products causing the volume to contacts by 6ml. The remaining mixture was passed through Pyragallol causing a contraction of 1ml. to the remaining mixture excess H_(2) was added and the above reaction was repeated, causing a reduction in volume of 1ml. assuming no other products to be forming calculate the volume of H_(2) (in ml) in the initial mixture.
Answer» Solution :`{:(H_(2(g)),,N_(2)(g),,O_(2(g))),(X+y,,x+1,,1+y),(H_(2(g)),+,O_(2(g)),to, H_(2)O_(2(L))),(x,,x,,),(H_(2(g)),+,N_(2(g)),to,N_(2)H_(2(g))),(y,,y,,y):}` 2x+2y=6 2x+2y+2=10 x+y=4 `UL(2x+y=6)` x=2 y=2