A mixture of `H_2C_2O_4` and `HCOOH` is heated with conc `H_2SO_4`. The gas produced is collected and on treatment with KOH solution, the volume of the gas decreases by `(1)/(6)` calculate the molar ratio of the two acids in the original mixture.

A mixture of `H_2C_2O_4` and `HCOOH` is heated with conc `H_2SO_4`. Th

1.	A mixture of `H_2C_2O_4` and `HCOOH` is heated with conc `H_2SO_4`. The gas produced is collected and on treatment with KOH solution, the volume of the gas decreases by `(1)/(6)` calculate the molar ratio of the two acids in the original mixture.
Answer» `H_2C_2O_4underset(triangle)overset(H_2SO_4)toH_2O+underset(y)(CO)+underset(y)(CO_2)` `underset(x)(HCOOH)underset(triangle)overset(H_2SO_4)toH_2O+underset(x)(CO)` Let x and y moles of HCOOH and `H_2C_2O_4` be present in the original mixture. Total moles of CO formed `=x+y` Moles of `CO_2` formed `=y` Total moles of gases `=x+y+y=x+2y` Since KOH solution absorbs `CO_2` and volume reduces by `(1)/(6)`. Moles of `CO_2(1)/(6)(x+2y)` `y=(1)/(6)(x+2y)` `(x)/(y)=4` `x:y::4:1`

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A mixture of `H_2C_2O_4` and `HCOOH` is heated with conc `H_2SO_4`. The gas produced is collected and on treatment with KOH solution, the volume of the gas decreases by `(1)/(6)` calculate the molar ratio of the two acids in the original mixture.

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