A mixture of `HCOOH` and `H_(2)C_(2)O_(4)` is heated with conc. `H_(2)SO_(4)`. The gas produced is collected and on treating with `KOH` solution the volume of the gas decreases by `1//6th`. Calculate molar ratio of two acids in original mixure.

A mixture of `HCOOH` and `H_(2)C_(2)O_(4)` is heated with conc. `H_(2)

1.	A mixture of `HCOOH` and `H_(2)C_(2)O_(4)` is heated with conc. `H_(2)SO_(4)`. The gas produced is collected and on treating with `KOH` solution the volume of the gas decreases by `1//6th`. Calculate molar ratio of two acids in original mixure.
Answer» `underset(1"mol")(HCOOH) underset("Heat")overset("Conc."H_(2)SO_(4))to underset(1"mol")(CO)+H_(2)O` `underset(1"mol")(H_(2)C_(2)O_(4)) underset("Heat")overset("Conc."H_(2)SO_(4))to underset(1"mol")(CO)+underset(1"mol")(CO_(2))+H_(2)O` Let a moles of HCOOH and b moles of `H_(2)C_(2)O_(4)` be present in the original mixture. `"Moles of CO formed "=a+b` `"Moles of " CO_(2) " formed "=b` Total moles of gases=a+b+b=a+2b `CO_(2)` is absorbed by KOH and the volume reduces by 1/6th. `"Moles of " =(a+2b)/(6)` `or b=(a+2b)/(6)` `or a=4b` `or (a)/(b)=4` `or a:b=4:1`

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A mixture of `HCOOH` and `H_(2)C_(2)O_(4)` is heated with conc. `H_(2)SO_(4)`. The gas produced is collected and on treating with `KOH` solution the volume of the gas decreases by `1//6th`. Calculate molar ratio of two acids in original mixure.

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