1.

A mixture of He and O_(2) has density 1.3 gm//litre at NTP. Them mole fraction of He is

Answer»

`0.1`
`0.9`
`0.4`
`0.6`

Solution :`d = 1.3 GM//"litre" = (PM)/(RT)`
`1.3 = (1 XX M)/(0.08 xx 273)`
`M = 1.3 xx 22.4`
`M = 29.12 gm//mol`
`M_(AVG) = M_(1)X_(1) xx M_(2) X_(2)`
`29.12 = 4a + 32 - 32a`
`29.12 = 32 - 28a`
`28a = 32 - 29.12`
`a = (2.88)/(28)`
`a = 0.1` Hence, `X_(O_(2)) = 0.9`
`X_(He) = 0.1`


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