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A mixture of two white substances is solubel in water. This solution gives brown colour gas on passing chlorine gas. Another sample of solution gives white precipitate with BaCl_(2) which is soluble in concentrated HCl. The original solution of the mixture gives white precipitate with large excess of NaOH solution whose suspension is used as an antacid. After filtering off this precipitate, the filtrate was boiled with excess NaOH. This solution gave a yellowish precipitate on addingNaClO_(4). Identify the mixture. |
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Answer» Solution :`2Br^(-)+Cl_(2)rarr 2CL^(-) +underset("brown")(Br_(2))` `CO_(3)^(2-)+BaCl_(2)rarr underset("white")(BaCo_(3)darr)+2Cl^(-)` `MG^(2+)+2NaOH rarr Mg(OH)_(2)+2NA^(+)` Therefore mixture consists `K_(2)CO_(3)` and `MgBr_(2)`. |
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