A mixtures of methane and ethylene in the volume ration x:y has total volume of 30mL. On complete combustion it gave 40mL of `CO_(2)`. IF the ratio of original mixture is y:x instead of x:y. What volume of `CO_(2)` would have been produced a combustion?A. 50mLB. 75mLC. 100mLD. 125mL

A mixtures of methane and ethylene in the volume ration x:y has total

1.	A mixtures of methane and ethylene in the volume ration x:y has total volume of 30mL. On complete combustion it gave 40mL of `CO_(2)`. IF the ratio of original mixture is y:x instead of x:y. What volume of `CO_(2)` would have been produced a combustion?A. 50mLB. 75mLC. 100mLD. 125mL
Answer» Correct Answer - A Combustion of `CH_(4) and C_(2)H_(4)` may be represented as. `"Combustion of "CH_(4) "may be represented as",` `underset(xmL)(CH_(4)(g))+2O_(2)(g) to underset(xmL)(CO_(2)(g))+2H_(2)O(g)` `underset(ymL)(C_(2)H_(4)(g))+3O_(2)(g) to underset(ymL)(2CO_(2)(g))+2H_(2)O(g)` Given, x+y=30 x+2y=40 `therefore x=20, y=10` When we take y mL `CH_(4) and "x mL" C_(2)H_(4)`, then volume of `CO_(2)` will be (y+2x), i.e. 50mL.

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A mixtures of methane and ethylene in the volume ration x:y has total volume of 30mL. On complete combustion it gave 40mL of `CO_(2)`. IF the ratio of original mixture is y:x instead of x:y. What volume of `CO_(2)` would have been produced a combustion?A. 50mLB. 75mLC. 100mLD. 125mL

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