1.

A model rocket is launched from the ground. The height 'h' reached by the rocket after t seconds from lift off is given by h(t) = -5t^(2) + 100t, 0 le t le 20. At what time the rocket is 495 feet above the ground?

Answer»


Answer :` THEREFORE 11 or 9 ` sec , the rocket is 495 feet above that ground .


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