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A modulating signal is a square wave as shown in figure. The carrier wave is given by c(t)=2 sin(8pit)"volt". (i) Sketch the amplitude modulated wave from (ii) What is the modulation index? |
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Answer» Solution :(`i`) Amplitude of modulating signal from fig is `A_(m)=1` Amplitude of carrier wave from the EQUATION is `A_(C)=2` Then maximum amplitude of modulated wave is `A_(max)=A_(c)+A_(m)` `, A_(max)=2+1=3` and MINIMUM amplitude of modulated wave is `A_(min)=A_(c)-A_(m)` Then the sketch for amplitude modulated wave is as below.  (`ii`) MODULATION index `MU=(A_(m))/(A_(c))=(1)/(2)=0.5` |
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