InterviewSolution
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InterviewSolution
| 1. |
A mole of steam is condensed at `100^(@)` C, the water is cooled to `0^(@)`C and frozen to i.e . What is the difference in entropies of the stem and ice? The heat of vaporization and fusion are `540 cal" "gm^(-1)` and `80 cal" "gm ^(-1)` respectively . Use the average heat capacity of liquild water as `1 cal" "gm^(-1)` `degree^(-1)`.A. Entropy change during the condensation of steam is `-26.06 cal//^(@)C`B. Entropy change during cooling of water from `100^(@)C "to" 0^(@)C "is" - 5.62 cal//^(@)C`C. Entropy change during freezing of water at `0^(@)C "is" -5.27 cal//^(@)C`D. Total entropy changwe is `-36.95 cal//^(@)C` |
| Answer» Correct Answer - A::B::C::D | |