InterviewSolution
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InterviewSolution
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A mole of steam is condensed at `100^(@)` C, the water is cooled to `0^(@)`C and frozen to i.e . What is the difference in entropies of the stem and ice? The heat of vaporization and fusion are `540 cal" "gm^(-1)` and `80 cal" "gm ^(-1)` respectively . Use the average heat capacity of liquild water as `1 cal" "gm^(-1)` `degree^(-1)`. |
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Answer» Correct Answer - B `DeltaS_("condensation")= (-DeltaH_("vap"))/(T)=(-540 xx 18)/(373)` `DeltaS_("cooling")= + nC_(p)ln .((T_(2))/(T_(2))) = 18 ln. ((273)/(373))` `DeltaS_("fusion") = (-80 xx 18)/(273)` `= - [18((80)/(273)+ (540)/(373)) + (18ln.(273)/(373))]` `= - 18((80)/(273) +(540)/(373)+ ln.(373)/(273))" "rArr 36.95 cal//^(@)` |
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