1.

A mole ofN_2 H_4 loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (There is no change in the oxidation number of hydrogen.)

Answer»

`-1`
`-3`
`+3`
`+5`

Solution :`N_2 H_4- 10 e^(-)toY ` ( withtwoN atoms )
totalO.Nof TWON atoms in `N_2 H_4` is
`2x +4 =0or2x=- 4`
sinceitloses10molesof ELECTRONS therefore , totalO.Nof twoN atomsincreasesby10i.e..,the totalO.NoftwoN atoms in
` y=- 4 +10= + 6`
` thereforeO.N ` of eachN atominY=+3


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