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A monatomic gas at pressure P1, and volume V1, iscompressed adiabatically to (1/8) th its original volumeWhat is the final presssure of the gas?(1) 64 P1(2) P1(3) 16 P1(4) 32 P1 |
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Answer» The correct answer is option (4) - 32 P1 Solution: Let’s assume the initial pressure to be P, final pressure to be P2 and initial volume to be V. It is given that for a monoatomic gas γ = 5/3 For adiabatic process PV^γ = constant PV^5/3=P (V/8)^5/3 P2 =P(8)^5/3 P2 = P ×2⁵ Therefore, P2 = 32P |
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