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A monkey of mass `20kg` is holding a vertical rope. The rope will not break when a mass of `25kg` is suspended from it but will break it the mass exeeds `25kg` . What is the maximum acceleration with which the monkey can climb up along the rope? `(g=10m//s^(2))` .A. `5 m//s^2`B. `10 m//s^2`C. `25 m//s^2`D. `2.5 m//s^2` |
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Answer» Correct Answer - D `T_"max"`=25 g , ma=`T_"max"`-mg `rArr a=g/4=10/4=2.5 m//s^2` |
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