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A mono-atomic gas `X` and an diatomic gas `gamma` both initially at the same temperature and pressure are compressed adiabatically from a volume `V` to `V//2`. Which gas will be at higher temperature?A. `X`B. `Y`C. both are sameD. Cannot be determined |
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Answer» `T_(1)V_(1)^(gamma-1) = T_(2)V_(2)^(gamma -1)` `:. (T_(2))/(T_(1)) = ((V_(1))/(V_(2)))^(gamma-1) = 2^(gamma-1)` Since `gamma` is more for the gas `X`, the temperature will also be more for it. |
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