1.

A mono energetic electron beam with a speed of ` 5.2xx10^(6) ms^(-1)` enters into a magnetic filed of induction ` 3xx10^(-4) T`, directed normal to the beam . Find the radius of the circul traced by the beam `(Take e//m=1.76xx10^(11) Ckg)`

Answer» From the eqation, `Bev =(mv^(2))/(r)`
Radius of circle `=(mv)/(Bq)= V/(B(e//m))`
`therefore r=(5.2xx10^(6))/(3xx10^(-4) (1.76xx10^(11)))=01.m`


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