InterviewSolution
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InterviewSolution
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A monoatomic gas undergoes a process given by `2dU+3dW=0`, then what is the process |
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Answer» `dQ=dU+dWrArrdQ=dU-(2dU)/(3)=(dU)/(3)` `=(1)/(3)nC,dT=(1)/(3)n(3)/(2)RdT=(nRdT)/(2)` `C=(1)/(n)(dQ)/(dT)=(R)/(2)` it is not isobaric as C is not equal to `(5R)/(2),` it is not adiabatic as `Ccancel=0` It is not isothermal as `Ccancel=oo` so it is a polytrophic process. |
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