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A monobasic weak acid solution has a molarity of 0.005 and pH of 5. What is its percentage ionization in this solution

Answer»

`2.0`
`0.2`
`0.5`
`0.25`

SOLUTION :`HA rarr H^(+) + A^(-)`
`K_(a) = ([H^(+)][A^(-)])/([HA]) , pH = -log[H^(+)]`
`[H^(+)] = 10^(-5) , [H^(+)] = [A^(-)]`
`K_(a) = (10^(-5) xx 10^(-5))/(0.005) = 2 xx 10^(-8)`
`ALPHA = sqrt((K_(a))/(C)) = 2 xx 10^(-3)`
Percentage ionization = 0.2


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