Saved Bookmarks
| 1. |
A monochromatic light is incident on asequallateral prism at an angle 30^(@) and emerge at an angle of 75^(@). What is the angle of deviation produced by the prism? |
|
Answer» Solution :Give: as the prism is equilateral. `A = 60^(@) , l_(1) = 30^(@) , l_(2) = 75^(@)` Equation for ANGLE of DEVIATION, `d = l_(1) + l_(2) - A` SUBSTITUTING the VALUES, `d = 30^(@) + 75^(@) - 60^(@) - 45^(@)` The angle of deviation produced is, `d - 45^(@)` |
|