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A monochromatic light is travelling in a medium of refractive index n = 1.6. It enters a stack of glass layers from the bottom side at an angle theta = 30^(@). The interfaces of the glass layers are parallel to each other. The refractive indices of different glass layers are monotonically decreasing as n_(m)=nmDeltan, where n_(m) is the refractive index of the m^(th) slab and Deltan = 0.1 (see the figure). The ray is refracted out parallel to the interface between the (m – 1)^(th) and m^(th) slabs from the right side of the stack. What is the value of m ? |
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Answer» `1.6 sin theta = n - m Delta n` `1.6 XX (1)/(2) = 1.6 - m(0.1)` `m xx 0.1 = 0.8` m = 8 MATHEMATICALLY answer is 8, but this value of refractive index is physically impossible. |
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