Saved Bookmarks
| 1. |
A monochromatic source of light operating at 200W emits 4 xx (10^20) photons per second. Find the wavelength of the light. |
|
Answer» SOLUTION : The energy of each photon = `(200 J(s^-1)/ 4 XX (10^20)(s^-1))` `= 5 xx (10^-19)J. ` `Wavelength= lambda= hc/E ` ` = ((6.63 xx (10^-34)J s) xx (3 xx (10^8)m(s^-1))/ ( 5 xx (10^-19)J)) ` ` = 4.0 xx (10^-7)m= 400 n m. ` |
|