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InterviewSolution
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A motor car travelling at `30 m//s` on a circular road of radius `500m`. It is increasing its speed at the rate of `2 ms^(-2)`. What its accleration at that instant ?A. `1.8ms^(-2)`B. `2ms^(-2)`C. `3.8ms^(-2)`D. `2.7ms^(-2)` |
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Answer» Correct Answer - d Radial acceleration `a_(r)=(v^(2))/r=((30)^(2))/500=1.8ms^(-2)` Tangential acceleration at `=2m//sec^(2)` Resultant acceleration `a^(2)=a_(r)^(2)+a_(t)^(2)+2a_(r)a_(t)cos theta` Here, `theta=90^(@)` `a^(2)=(1.8)^(2)+(2)^(2)+0=3.24+4=7.24` `a=sqrt(7.24)=2.7 ms^(-2)` |
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