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A motorcycle is running with a velocity of 54 km/h is brought to rest in 5 seconds by applying brakes. Distance covered by the motorcycle at the end of 5 seconds is |
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Answer» Explanation:Given,INITIAL velocity of the MOTORCYCLE, u = 54 km/h = 54 × 5/18 = 15 m/sFinal velocity of the motorcycle, v = 0 m/s (As brakes applied)Time taken by the motorcycle, t = 5 secondsTo Find,Distance covered by the motorcycle, s = ?Formula to be used,1st equation of motion, v = u + at3rd equation of motion, v² - u² = 2asSolution,At 1st we will find acceleration,Putting all the VALUES, we getv = u + at⇒ 0 = 15 + a × 5⇒ - 15 = 5a⇒ - 15/5 = a⇒ a = - 3 m/s²Here, the acceleration is - 3 m/s².Now, the distance covered,v² - u² = 2as⇒ (0)² - (15)² = 2 × (- 3) × s⇒ 225 = - 6s⇒ 225/6 = s⇒ s = 37.5 mHence, the Distance covered by the motorcycle is 37.5 m. |
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