A moving coil galvanometer has a current sensitivity of 10div/mA and voltage sensitivity of 5div/volt. The instrument has 50 divisions. Calculate the resistance of the galvanometer. DATA: No. of divisions=50 Current sensitivity = 10 div/mA therefore Maximum current = 50/10 5mA = 5xx10^(-3) A Voltage sensitivity = 5 div/volt therefore Maximum P.D = 50/5=10V To find: resistance=?

A moving coil galvanometer has a current sensitivity of 10div/mA and v

1.	A moving coil galvanometer has a current sensitivity of 10div/mA and voltage sensitivity of 5div/volt. The instrument has 50 divisions. Calculate the resistance of the galvanometer. DATA: No. of divisions=50 Current sensitivity = 10 div/mA therefore Maximum current = 50/10 5mA = 5xx10^(-3) A Voltage sensitivity = 5 div/volt therefore Maximum P.D = 50/5=10V To find: resistance=?
Answer» Solution :RESISTANCE(GALVANOMETER) `=(P.D.)/(max. current)=(10)/(5XX10^(-3))=2000Omega`

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