1.

A moving electron has 4.55 xx 10^(-25) joules of kinetic energy. Calculate its wavelength (mass = 9.1 xx 10^(-31) kg and h = 6.626 xx 10^(-34) kg m^2 s^(-1) ).

Answer»

Solution :Here we given
kinetic ENERGY `1/2 mv^2 = 4.55 xx 10^(-25) J`
`m = 9.1 xx 10^(-31) KG `
`h = 6.626 xx 10^(-34) kg m^2 s^(-1)`
` therefore 1/2 xx (9.1 xx 10^(-31) ) v^2 = 4.55 xx 10^(-25)`
` v^2= (4.55 xx 10^(-25) xx 2)/(9.1 xx 10^(-31)) = 10^6`
` v = 10^3 ms^(-1)`
` therefore lamda = (h)/(mv) = (6.626 xx 10^(-34))/((9.1 xx 10^(-31) ) xx 10^3)`
` = 7.25 xx 10^(-7) m`


Discussion

No Comment Found

Related InterviewSolutions