1.

A n-p-n transistor is connected in C - E configuration Collector supply is 8 V . The voltage drop across the load resistor of 800Omega , connected to collector circuit is 0.8 volt . If alpha = 25/26 Then collector emitter voltage (V_("ce")) is

Answer»

5.2 V
6.2 V
7.2 V
8.2 V

Solution :Current gain , `alpha =25//26`
`:. ""beta = alpha/(1- alpha) =(25//26)/(1-25//26)=25`
Collector supply voltage E = 8 V
Output voltage `V_0 = 0.8 V`
`:. V_("CE")=E-V_0= 8 xx 0.8 = 7.2 V`


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