Saved Bookmarks
| 1. |
A narrow beam of light is incident on a glass plate of refractive index 1.6. It makes an angle 53^@ with normal to the interface. Find the lateral shift of the beam at the point of emergence, if thickness of the plate is 30 mm. (Take sin53^@ = 0.8.) |
|
Answer» 9.023 mm `n_1sintheta_1=n_2sin theta_2` (1) `sin53^@=1.6sintheta_2` 0.7986=1.6`sintheta_2` `thereforesin theta_2=(0.7986)/(1.6)=0.4991 ~~0.5 " rad "=30^@` Now, LATERAL shift, `x=(TSIN(theta_1-theta_2))/(costheta_2)` `=(30sin(53^@-30^@))/(COS30^@)=(30sin23^@)/(cos30^@)` `=(30xx0.3907)/(0.866)=13.53` mm |
|