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A narrow beam of natural light falls on the surface of a thick transparent plane-parallel plate at the Brewster angle. Its top surface. Find the degree of polarization of beams 1-4 (Fig.) |
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Answer» Solution :SINCE natural light is incident at the BREWSTER's angle, the reflected light `1` is complately polarized and `P_(1) = 1`. Similarly the ray `2` is incident on GLASS air surface at Brewster's angle `(tan^(-1).(1)/(n))` so `3` is also completely polarized. Thus `P_(3) = 1` Now as in `5.167(b)` `P_(2) = (rho)/(1 - rho) = 0.087` if `rho =0.080`   Finally as shown in the figure `P_(4)= ((1)/(2)-(1)/(2)(1-2rho)^(2))/((1)/(2)+(1)/(2)(1-2rho)^(2)) =(2rho(1-rho))/(1-2rho(1-rho)) = 0.173` |
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