1.

A narrow tube is bend in the form of a circle of radius R, as shown in the figure. Two small holes S and D are made in the tube at the positions right angle to each other. A source placed at S generated a wave of intensity `I_(0)` which is equally divided into two parts : One part travels along the longer path, while the other travels along the shorter path. Both the parts wave meet at the point D where a detector is placed. The maximum intensity produced at D is given by :-A. `4 I_(0)`B. `2 I_(0)`C. `I_(0)`D. `3 I_(0)`

Answer» Correct Answer - B
`I_(max)=(sqrt((I_(0))/(2))+sqrt((I_(0))/(2)))^(2)=2I_(0)`


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