A natural number is chosen at random from the first 100 naturalnumbers. The probability that `x+(100)/x > 50`is`1//10`b. `11//50`c. `11//20`d. none of theseA. `1//10`B. `11/50`C. `11/20`D. none of these

A natural number is chosen at random from the first 100 naturalnumbers

1.	A natural number is chosen at random from the first 100 naturalnumbers. The probability that `x+(100)/x > 50`is`1//10`b. `11//50`c. `11//20`d. none of theseA. `1//10`B. `11/50`C. `11/20`D. none of these
Answer» Correct Answer - C We have, `x + (100)/(x) gt 50` or `x^(2) + 100 gt 50x` or `(x - 25)^(2) gt 525` `implies x - 25 lt - sqrt(525) or x - 25 sqrt(525)` `implies x lt 25 - sqrt(525) or x gt 25 + sqrt(525)` As x is a positive integer and `sqrt(525)` = 22.91, we must have `x le 2` or `x ge 48`. Thus, the favorable number of cases is 2 + 53 = 55. Hence, the required probability is `55//100` = `11//20`.

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A natural number is chosen at random from the first 100 naturalnumbers. The probability that `x+(100)/x > 50`is`1//10`b. `11//50`c. `11//20`d. none of theseA. `1//10`B. `11/50`C. `11/20`D. none of these

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