1.

A negatively charged oil drop is prevented from failing under gravity by applying a vertical electric field 100 Vm^(-1). If the mass of the drop is 1.6 xx 10^(-3)g the number of electrons carried by the drop is (g=10 ms^(-2))

Answer»

`10^(18)`
`10^(15)`
`10^(6)`
`10^(12)`



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