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A negligibly small current is passed through a wire of length 20 m and uniform cross-section 6.0 xx 10^(7) m^(2), and its resistance is measured to be 10.0 Omega . What is the resistivity of the material at the temperature of the experiment ? |
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Answer» Solution :Resistance of a CONDUCTING WIRE is R = `(rho l)/(A)` `rho = (RA)/(l)` `= (5 xx 6 xx 10^(7))/(15)` `rho = 2 xx 10^(-7) Omega` m |
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