1.

A neutral compound with molecular formula C_(3)H_(8)O evolves H_(2) when treated with sodium metal and gives iodoform test. The compound is

Answer»

`(CH_(3))_(2)CHOH`
`CH_(3)CH_(2)CH_(2)OH`
`CH_(3)COCH_(3)`
`CH_(3)CH_(2)CHO`

SOLUTION :Since the compound evolves `H_(2)` on treatment with Na metal, it must contain an OH group. Further, since it gives iodoform test, therefore, it must contain the GROUPING `CH_(3)CHOH` - or `CH_(2)CO` - Both these reactions are given by compound, `(CH_(3)),CHOH` or `CH_(2)CHOHCH_(3)`.


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