A neutral point is found on the prolongation of the axis of a bar magnet of length 10 cm at 10 cm from the nearer pole. How has the magnet been placed with respect to the magnetic meridian ? Calculate the magnetic moment of the magnetic given that B-vector of earth's field along the horizontal = 3.6 xx 10^(-5) tesla. Also calculate the torque required to deflect it through 30^(@) from the magnetic meridian.

A neutral point is found on the prolongation of the axis of a bar magn

1.	A neutral point is found on the prolongation of the axis of a bar magnet of length 10 cm at 10 cm from the nearer pole. How has the magnet been placed with respect to the magnetic meridian ? Calculate the magnetic moment of the magnetic given that B-vector of earth's field along the horizontal = 3.6 xx 10^(-5) tesla. Also calculate the torque required to deflect it through 30^(@) from the magnetic meridian.
Answer» Answer :`0.48 Am^(2), 8.64 XX 10^(-6)NM`

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