1.

A neutron causes fission in ""_(92)U^(235) producing ""_(40)Zr^(97), Te^(134) and some neutrons. What is at no. of Te and how many neutrons are released?

Answer»

82,7
52,4
26,2
13,1

Solution :`""_(92)U^(235)=""_(40)ZR^(97)+""_(z)Te^(134)+x_(0)n^(1)` CONSERVING at numbers, x is no. of NEUTRONS
`92=40+z rArr z=52`
Conserving mass number, `235=97+134+x`
`x=4`


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