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A neutron moving with a speed `v` makes a head-on collision with a hydrogen in ground state kept at rest which inelastic collision will be take place is (assume that mass of photon is nearly equal to the mass of neutron)A. `10.2eV`B. `20.4eV`C. `12.1eV`D. `16.8eV` |
Answer» Correct Answer - B Let V=speed of neutron before collision `v_(1)`=speed of neutron after collision ` v_(2)`= speed of proton or hydrogen atom after collision and `DeltaE`= energy of exitation. From conservation of linear momentum `mv=mv_(1)+mv_(2)` ...(1) From conservation of energy ` 1/2mv^(2)=1/2mv_(1)^(2)+1/2mv_(2)^(2)+DeltaE` ...(2) from `1`and `2`As `v_(1)-v_(2)` must be real `v^(2)-4(DeltaE)/mge0` ` Rightarrow1/2mv^(2)=2DeltaE=2xx10.2=20.4eV` |
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